Given an array, find the pair of entries that have difference k.
Given an array of integers nums
and an integer k
, return the number of unique k-diff pairs in the array.
A k-diff pair is an integer pair (nums[i], nums[j])
, where the following are true:
0 <= i < j < nums.length
|nums[i] - nums[j]| == k
Notice that |val|
denotes the absolute value of val
.
Example 1:
Input: nums = [3,1,4,1,5], k = 2 Output: 2 Explanation: There are two 2-diff pairs in the array, (1, 3) and (3, 5). Although we have two 1s in the input, we should only return the number of unique pairs.
Example 2:
Input: nums = [1,2,3,4,5], k = 1 Output: 4 Explanation: There are four 1-diff pairs in the array, (1, 2), (2, 3), (3, 4) and (4, 5).
Example 3:
Input: nums = [1,3,1,5,4], k = 0 Output: 1 Explanation: There is one 0-diff pair in the array, (1, 1).
Example 4:
Input: nums = [1,2,4,4,3,3,0,9,2,3], k = 3 Output: 2
Example 5:
Input: nums = [-1,-2,-3], k = 1 Output: 2
Constraints:
1 <= nums.length <= 104
-107 <= nums[i] <= 107
0 <= k <= 107
This is an interesting problem that is also discussed in Page1, LeetCode and several other forums such as Page2, Page3 A collection of hundreds of interview questions and solutions are available in our blog at Interview Question
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