// Given an unsorted array of integers, find the length of the longest consecutive elements sequence.
// For example,
// Given [100, 4, 200, 1, 3, 2],
// The longest consecutive elements sequence is [1, 2, 3, 4]. Return its length: 4.
// Your algorithm should run in O(n) complexity.
public class LongestConsecutiveSequence {
public int longestConsecutive(int[] nums) {
int res = 0;
HashMap<Integer, Integer> map = new HashMap<Integer, Integer>();
for(int n : nums) {
if(!map.containsKey(n)) {
int left = (map.containsKey(n - 1)) ? map.get(n - 1) : 0;
int right = (map.containsKey(n + 1)) ? map.get(n + 1) : 0;
int sum = left + right + 1;
res = Math.max(res, sum);
map.put(n, sum);
map.put(n - left, sum);
map.put(n + right, sum);
} else {
continue;
}
}
return res;
}
}
// For example,
// Given [100, 4, 200, 1, 3, 2],
// The longest consecutive elements sequence is [1, 2, 3, 4]. Return its length: 4.
// Your algorithm should run in O(n) complexity.
public class LongestConsecutiveSequence {
public int longestConsecutive(int[] nums) {
int res = 0;
HashMap<Integer, Integer> map = new HashMap<Integer, Integer>();
for(int n : nums) {
if(!map.containsKey(n)) {
int left = (map.containsKey(n - 1)) ? map.get(n - 1) : 0;
int right = (map.containsKey(n + 1)) ? map.get(n + 1) : 0;
int sum = left + right + 1;
res = Math.max(res, sum);
map.put(n, sum);
map.put(n - left, sum);
map.put(n + right, sum);
} else {
continue;
}
}
return res;
}
}
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