//Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times.
//You may assume that the array is non-empty and the majority element always exist in the array.
class MajorityElement {
public int majorityElement(int[] nums) {
if(nums.length == 1) {
return nums[0];
}
HashMap<Integer, Integer> map = new HashMap<Integer, Integer>();
for(int current: nums) {
if(map.containsKey(current) && map.get(current) + 1 > nums.length / 2) {
return current;
} else if(map.containsKey(current)) {
map.put(current, map.get(current) + 1);
} else {
map.put(current, 1);
}
}
//no majority element exists
return -1;
}
}
//You may assume that the array is non-empty and the majority element always exist in the array.
class MajorityElement {
public int majorityElement(int[] nums) {
if(nums.length == 1) {
return nums[0];
}
HashMap<Integer, Integer> map = new HashMap<Integer, Integer>();
for(int current: nums) {
if(map.containsKey(current) && map.get(current) + 1 > nums.length / 2) {
return current;
} else if(map.containsKey(current)) {
map.put(current, map.get(current) + 1);
} else {
map.put(current, 1);
}
}
//no majority element exists
return -1;
}
}
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