// Find the contiguous subarray within an array (containing at least one number)
//which has the largest product.
// For example, given the array [2,3,-2,4],
// the contiguous subarray [2,3] has the largest product = 6.
public class MaximumProductSubarray {
public int maxProduct(int[] nums) {
if(nums == null || nums.length == 0) {
return 0;
}
int result = nums[0];
int max = nums[0];
int min = nums[0];
for(int i = 1; i < nums.length; i++) {
int temp = max;
max = Math.max(Math.max(nums[i] * max, nums[i] * min), nums[i]);
min = Math.min(Math.min(nums[i] * temp, nums[i] * min), nums[i]);
if(max > result) {
result = max;
}
}
return result;
}
}
//which has the largest product.
// For example, given the array [2,3,-2,4],
// the contiguous subarray [2,3] has the largest product = 6.
public class MaximumProductSubarray {
public int maxProduct(int[] nums) {
if(nums == null || nums.length == 0) {
return 0;
}
int result = nums[0];
int max = nums[0];
int min = nums[0];
for(int i = 1; i < nums.length; i++) {
int temp = max;
max = Math.max(Math.max(nums[i] * max, nums[i] * min), nums[i]);
min = Math.min(Math.min(nums[i] * temp, nums[i] * min), nums[i]);
if(max > result) {
result = max;
}
}
return result;
}
}
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