LeetCode: Pacific Atlantic Water Flow

// Given an m x n matrix of non-negative integers representing the height of each unit cell in a continent, the "Pacific ocean" touches the left and top edges of the matrix and the "Atlantic ocean" touches the right and bottom edges.

// Water can only flow in four directions (up, down, left, or right) from a cell to another one with height equal or lower.

// Find the list of grid coordinates where water can flow to both the Pacific and Atlantic ocean.

// Note:
    // The order of returned grid coordinates does not matter.
    // Both m and n are less than 150.

// Example:

// Given the following 5x5 matrix:

//   Pacific ~   ~   ~   ~   ~
//        ~  1   2   2   3  (5) *
//        ~  3   2   3  (4) (4) *
//        ~  2   4  (5)  3   1  *
//        ~ (6) (7)  1   4   5  *
//        ~ (5)  1   1   2   4  *
//           *   *   *   *   * Atlantic

// Return:

// [[0, 4], [1, 3], [1, 4], [2, 2], [3, 0], [3, 1], [4, 0]] (positions with parentheses in above matrix).

public class PacificAtlanticWaterFlow {
    public List<int[]> pacificAtlantic(int[][] matrix) {
        List<int[]> result = new LinkedList<>();
     
        //error checking
        if(matrix == null || matrix.length == 0 || matrix[0].length == 0) {
            return result;
        }
     
        int n = matrix.length;
        int m = matrix[0].length;
     
        boolean[][] pacific = new boolean[n][m];
        boolean[][] atlantic = new boolean[n][m];
     
        for(int i = 0; i < n; i++) {
            dfs(matrix, pacific, Integer.MIN_VALUE, i, 0);
            dfs(matrix, atlantic, Integer.MIN_VALUE, i, m - 1);
        }
     
        for(int i = 0; i < m; i++) {
            dfs(matrix, pacific, Integer.MIN_VALUE, 0, i);
            dfs(matrix, atlantic, Integer.MIN_VALUE, n - 1, i);
        }
     
        for(int i = 0; i < n; i++) {
            for(int j = 0; j < m; j++) {
                if(pacific[i][j] && atlantic[i][j]) {
                    result.add(new int[] {i, j});
                }
            }
        }
     
        return result;
    }
 
 
    public void dfs(int[][] matrix, boolean[][] visited, int height, int x, int y) {
        int n = matrix.length;
        int m = matrix[0].length;
     
        if(x < 0 || x >= n || y < 0 || y >= m || visited[x][y] || matrix[x][y] < height) {
            return;
        }
     
        visited[x][y] = true;
     
        dfs(matrix, visited, matrix[x][y], x + 1, y);
        dfs(matrix, visited, matrix[x][y], x - 1, y);
        dfs(matrix, visited, matrix[x][y], x, y + 1);
        dfs(matrix, visited, matrix[x][y], x, y - 1);
    }
}