//Given an array of integers, every element appears three times except for one,
//which appears exactly once. Find that single one.
//Note:
//Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
class SingleNumberII {
public int singleNumber(int[] nums) {
HashMap<Integer, Integer> map = new HashMap<Integer, Integer>();
for(int i: nums) {
if(map.containsKey(i)) {
map.put(i, map.get(i) + 1);
} else {
map.put(i, 1);
}
}
for(int key: map.keySet()) {
if(map.get(key) == 1) {
return key;
}
}
//no unique integer in nums
return -1;
}
}
//which appears exactly once. Find that single one.
//Note:
//Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
class SingleNumberII {
public int singleNumber(int[] nums) {
HashMap<Integer, Integer> map = new HashMap<Integer, Integer>();
for(int i: nums) {
if(map.containsKey(i)) {
map.put(i, map.get(i) + 1);
} else {
map.put(i, 1);
}
}
for(int key: map.keySet()) {
if(map.get(key) == 1) {
return key;
}
}
//no unique integer in nums
return -1;
}
}
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