// Given a collection of integers that might contain duplicates, nums, return all possible subsets.
// Note: The solution set must not contain duplicate subsets.
// For example,
// If nums = [1,2,2], a solution is:
// [
// [2],
// [1],
// [1,2,2],
// [2,2],
// [1,2],
// []
// ]
public class SubsetsII {
public List<List<Integer>> subsetsWithDup(int[] nums) {
Arrays.sort(nums);
List<List<Integer>> result = new ArrayList<List<Integer>>();
if(nums.length == 0 || nums == null) {
return result;
}
helper(nums, new ArrayList<Integer>(), 0, result);
return result;
}
public void helper(int[] nums, ArrayList<Integer> current, int index, List<List<Integer>> result) {
result.add(current);
for(int i = index; i < nums.length; i++) {
if(i > index && nums[i] == nums[i - 1]) {
continue;
}
ArrayList<Integer> newCurrent = new ArrayList<Integer>(current);
newCurrent.add(nums[i]);
helper(nums, newCurrent, i + 1, result);
}
}
}
// Note: The solution set must not contain duplicate subsets.
// For example,
// If nums = [1,2,2], a solution is:
// [
// [2],
// [1],
// [1,2,2],
// [2,2],
// [1,2],
// []
// ]
public class SubsetsII {
public List<List<Integer>> subsetsWithDup(int[] nums) {
Arrays.sort(nums);
List<List<Integer>> result = new ArrayList<List<Integer>>();
if(nums.length == 0 || nums == null) {
return result;
}
helper(nums, new ArrayList<Integer>(), 0, result);
return result;
}
public void helper(int[] nums, ArrayList<Integer> current, int index, List<List<Integer>> result) {
result.add(current);
for(int i = index; i < nums.length; i++) {
if(i > index && nums[i] == nums[i - 1]) {
continue;
}
ArrayList<Integer> newCurrent = new ArrayList<Integer>(current);
newCurrent.add(nums[i]);
helper(nums, newCurrent, i + 1, result);
}
}
}
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